Daniil Medvedev on Saturday defeated Filip Krajinovic 6-3, 6-3, 4-6, 3-6, 6-0 to reach the fourth round of the Australian Open . With this victory,World No. four reached to the fourth round  for the third consecutive year. He also extended his winning streak to 17 matches, which include the title at the 2020 season-ending ATP Finals.

In the match, Medvedev was 0-6 in five-setters, including his brilliant 2019 US Open championship match against Rafael Nadal. But despite letting slip a two-set advantage against Krajinovic, the Russian steadied himself to triumph after three hours and six minutes.

In the third-round clash, the Medvedev defeated Krajinovic in the first two sets and it almost looked like an easy encounter for the 2019 US Open finalist. But in the third set, the Serbian came out with all guns blazing and made a comeback by clinching the set 6-4. Krajinovic continued the momentum in winning the fourth set by 6-3 but Medvedev bagged the set and match without losing any point in the fifth set.

Medvedev will next play Mackenzie McDonald, the unseeded American, in the fourth round of the tournament. 

Also Read: 

Both Davies, Kabak have great attitude: Klopp

Ind VS Eng: Rohit Sharma became the first Indian batsman to hit 200 sixes

Ind Vs Eng: Virat Kohli bold by Moin Khan in second Test