JEE Main 2019 result has been declared last evening. Candidates who wish to appear for the JEE Advanced examination are required to appear for and score a minimum marks in JEE Main to qualify for JEE Advanced 2019. NTA has also released the JEE Main cut off for the IIT JEE examination.

As many as 24 candidates have scored a perfect 100 percentile to top JEE Main 2019 examinations (April and January combined).

This year the cut off would be based on the NTA score which is a percentile measure of the students’ performance. JEE Main 2019 cut off for JEE Advanced is tabulated below. Please note, the status of candidates to qualify from the various category would be available on their JEE Main 2019 Result window.

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The candidates who have qualified for JEE Advanced are now required to fill the online application forms on the official website jeeadv.ac.in. Please note, the online application forms for JEE Advanced would open from May 3, 2019 and close on May 8, 2019. Candidates are required to apply online and pay the fees.

JEE Main 2019 Cut-off of Total NTA Score Based on Paper-I for JEE Advanced 2019

Common Rank List (CRL)- 89.7548849

Economically Weaker Section (EWS)- 78.2174869

Other Backward Class (OBC-NCL)- 74.3166557

Scheduled Caste (SC)- 54.0128155

Scheduled Tribe (ST)- 44.3345172

People with Disability (PwD)- 0.1137173

According to  a rough estimate suggests that more than 2.5 lakh candidates have qualified for the JEE Advanced which is the entrance test for Indian Institutes of Technology or IIT.

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JEE Advanced 2019 examination date was postponed. Due to general elections 2019, JEE Advanced would now be conducted on May 27, 2019. The paper would be completely Computer Based Test.