London: in the 14th match of the World Cup against Australia, Indian team opener Rohit Sharma played an impressive semi-first inning of 57 runs and was partnered with Shikhar Dhawan to score a quick-wicket partnership. According to the sources, Rohit had a special record with this innings. Rohit completed his 2000 runs against Australia in Monodini cricket. He has touched this figure in 37 innings. He is the first Indian to score 2000 or more in the lowest innings against any team. The record before him was Sachin Tendulkar's name. Sachin had touched the figure in 40 innings. With this, Sachin had completed his 2000 ODI runs against Australia. So far, 4 batsmen have been able to score 2000 or more against Australia in ODIs. Among them is Sachin, Rohit besides West Indies ' Desmond Haynes and Vivian Richards. It is noteworthy that the Indian team has set a target of 353 runs to win over Australia in the match. India scored 352 for five in the stipulated 50 overs. For the Indian team, apart from Dhawan, Kohli, and Rohit, Hardik Pandya (48 runs 27 balls) was the quickest to Mahendra Singh Dhoni (27 runs 14 balls). also read: World Cup 2019: West Indies to battle against Africa today