India's ace shuttler PV Sindhu beat He Bing Jiao of China to win the women's singles bronze medal at Tokyo Olympics. With this win, Sindhu became the first Indian woman to win two individual Olympic medals. Sindhu ruled Bing Jiao 21-13, 21-15 as she swayed off the misfortune of losing the semi-final to Chinese Taipei's Tai Tzu Ying on Saturday. She had won silver at Rio Olympics in 2016 after losing to Spain's Carolina Marin in the final.

Having suffered a heartbreaking loss to Chinese Taipei's Tai Tzu Ying in the semi-finals on Saturday, Sindhu came out with determination on Sunday and stamped her authority in the bronze medal match, right from the start. She raced to a 4-0 lead, setting down an early marker. He Bing Jiao clawed her way back to make it 5-5 and then made it 6-5 to lead for the first time in the match. Sindhu rumbled back to life, leaving her Chinese opponent struggling around the court. Some more authoritative shots put the Indian 11-8 ahead at the mid-game interval of the first game. Not only were Sindhu's dominant smashes causing problems for He Bing Jiao but her ability to retrieve made sure that the Chinese had to work doubly hard to win points.

Sindhu's power and cleverness proved just too much for Bing Jiao as the Indian took the first game 21-13. Like in the first, Sindhu was quick out of the blocks and came out all guns blazing in the second and took a 4-1 lead, going on to open a 11-8 lead in the mid-break. He Bing Jiao showed some fight to make it 11-11 but Sindhu once again upped the ante and started to pull away. The Chinese tried to stay in touch but Sindhu was possessing none of it. The Indian star made it 19-15 before winning two more consecutive points to finish things off.

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