New Delhi: The second match of the three-match T20 series between Team India and Australia is to be played at the Vidarbha Cricket Association Stadium in Nagpur today. In this match, Team India captain Rohit Sharma has a chance to create history. If Rohit hits a single six against Australia today, he will become the sixer king of the shortest format of cricket.
Rohit Sharma has so far hit 172 sixes in 137 T20I matches, he is at the top with New Zealand opening batsman Martin Guptill, who also has the same number of sixes to his name. If Rohit hits a single six today, he will make a world record for most sixes in T20 International. Rohit and Guptill are followed by Universal Boss Chris Gayle, who has hit 124 sixes in 79 matches. At the same time, Eoin Morgan (120) is in fourth place and Australia captain Aaron Finch (118) is at number five.
At the same time, talking about the batsmen who have scored the most runs in this format, Rohit Sharma is ruling here too. Rohit has 3,631 runs in T20I and he is in first place on the list of batsmen who have scored the most runs. He is followed by former Team India captain Virat Kohli, who has scored 3,586 runs in 97 matches. At the same time, New Zealand's Martin Guptill is in third place with 3,497 runs.
Let me tell you that the second T20 match against Australia is going to be a do-or-die for India. In fact, in the first match of the series, Team India had to face defeat by 4 wickets. India is trailing 0-1 in the three-match series. If India loses in Nagpur today too, they will lose the series.
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